Match Pattern (G Dataflow)

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Last Modified: August 31, 2018

Searches for a pattern of characters in a string as specified by a limited set of regular expressions.

If this node finds a match, it splits the input string into three substrings: the string that appears before the match, the match itself, and the string that appears after the match.

This node performs more quickly than Match Regular Expression but gives you fewer options for matching strings. For example, Match Pattern does not support the parenthesis or vertical bar (|) characters.

string

The input string to search.

regular expression

The pattern for which you want to search in the input string. This input is limited to the following regular expression characters: . (period), *, +, ?, [], ^, $, \, \b, \f, \n, \s, \r, \t, and \xx. Furthermore, this input does not support character grouping, alternate pattern matching, backreferences, or non-greedy quantification.

Definitions of Special Characters

Special Character	Description	Examples
. (period)	Matches any single character except a newline character. Within square brackets, . is literal.	Input String: Welcome to LabVIEW. Regular Expression: t.... Match: to La If you use [z.] as the regular expression, the period is literal and matches either . or z. In this example, [z.] returns . as the match.
*	Marks the single preceding character or character class as one that can appear zero or more times in the input. Because an asterisk can mark a pattern as one that appears zero times, regular expressions that include an asterisk can return an empty string if the whole pattern is marked with an asterisk. This quantifier applies to as many characters as possible.	Input String: Hello LabVIEW! Regular Expression: el* Match: ell Expressions such as w* or (welcome)* match an empty string if the node finds no other matches.
+	Marks the single preceding character or character class as one that can appear one or more times in the input. This quantifier applies to as many characters as possible.	Input String: Hello LabVIEW! Regular Expression: el+ Match: ell
?	Marks the single preceding character or character class as one that can appear zero or one time in the input. This quantifier applies to as many characters as possible.	Input String: Hello LabVIEW! Regular Expression: el? Match: el
[]	Creates a character class, which allows you to match any one of a set of characters that you specify. For example, [abc] matches a, b, or c. This node interprets special characters inside square brackets literally, with the following exceptions: - (dash)—Indicates a range when used between digits, or lowercase or uppercase letters; for example, [0-5], [a-g], or [L-Q]. ~—Matches any character, including non-displayable characters, except for the characters or range of characters in brackets. For example, [~0-9] matches any character other than 0 through 9. ^—Matches any displayable character, including the space character, except the characters or range of characters enclosed in the brackets. For example, [^0-9] matches all displayable characters, including the space character, except 0 through 9.	Input String: version=14.0.1 Regular Expression: [0-9]+\.[0-9]+\.[0-9]+ Match: 14.0.1 The expression [0-9] matches any digit. The plus sign matches the previous character class, [0-9], one or more times but as many times as possible. The expression \. matches a literal . character. The plus sign matches the previous character class, [0-9], one or more times but matches as many times as possible. You can use this regular expression to match a three-part version number.
^	If ^ is the first character of the specified search string, it anchors the match to the offset in string. The match fails unless the specified search string matches that portion of string that begins with the character at offset. If ^ is not the first character in the regular expression, it is treated as a regular character.	Input String: Hello LabVIEW! Regular Expression: ^[^ ]+ Match: Hello From the beginning of the input string, this regular expression matches as many characters – other than a space character – as possible. You can use this regular expression to isolate the first word, numeral, or other character combination of a string.
$	If $ is the last character of the specified search string, it anchors the match to the last element of string. The match fails unless the specified search string matches up to and including the last character in the string. If $ is not the last character in the regular expression, it is treated as a regular character.	Input String: Hello LabVIEW! Regular Expression: [^ ]+$ Match: LabVIEW! From the end of the input string, this regular expression matches as many characters – other than a space character – as possible. You can use this regular expression to isolate the last word, numeral, or other character combination of a string.
\	Cancels the interpretation of any special character in this list. For example, \? matches a question mark, \. matches a period, and \\ matches a backslash. You also can use the following constructions for the following non-displayable characters: \b—Backspace \f—Form feed \n—New line \s—Space \r—Carriage return \t—Tab \xx—Any character, where xx is the hex code using 0 through 9 and upper case A through F.	Input String: Welcome to the LabVIEW Help! Regular Expression: come\nto\tthe\sLabVIEW\sHelp\21 Match: come to the LabVIEW Help! The expression come\n matches the literal letters followed by a newline character. The expression to\t matches the literal characters to followed by a tab. The two \s expressions match the spaces between the and LabVIEW and between LabVIEW and Help!. The expression \21 matches the exclamation point because 21 is the hexadecimal code for an exclamation point.

Note

If you want to include special characters in the search string, you must enclose each special character in brackets. For example, to search for the string hz+, enter hz[+] in the specified search string. Otherwise, the node uses the special character to refine the search.

offset

The number of characters into the input string at which this node begins its operation.

The offset of the first character in the input string is 0. If offset is beyond the end of the input string, this node returns an empty string.

Note

A character refers to a code point, a numeric unit between 0 and 10FFFF₁₆, defined by the Unicode standard for encoding. For more information about code points, research Unicode.

Default: 0

before substring

A string containing all the characters in the input string that occur before the match.

match substring

First string after the offset that matches the pattern specified by the regular expression.

after substring

String containing all characters in the input string that follow the match.

offset past match

The index in the input string of the first character of after substring. If the node does not find a match, this output returns -1.

Note

A character refers to a code point, a numeric unit between 0 and 10FFFF₁₆, defined by the Unicode standard for encoding. For more information about code points, research Unicode.

What Happens When There Is No Match?

If the node does not find regular expression, match substring is empty, before substring is the entire string, after substring is empty, and offset past match is -1. Match Pattern is compatible with a limited set of regular expressions and does not support character grouping, alternate pattern matching, backreferences, or non-greedy quantification. You can use a specific set of special characters to refine the search.

string	regular expression	offset	match	offset past match	Comments
cdb	b*	0	""	0	The offset input and the offset past match output might be equal when the empty string is a valid match for the regular expression.
bbbcd	b*	0	bbb	3	Notice that offset does not equal offset past match because a longer match than the empty string existed.

Where This Node Can Run:

Desktop OS: Windows

FPGA: All devices (only within an optimized FPGA VI)

Web Server: Supported in VIs that run in a web application

Table Of Contents

string

regular expression

offset

before substring

match substring

after substring

offset past match

What Happens When There Is No Match?

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